factorise each of the following polynomial 1 4ycube + 20ysq + 33y +18 given that 2y + 3 is a factor
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4y^3+20y^2+33y+18
y=-3/2
4(-3/2)^3+20(-3/2)^2+33(-3/2)+18
4×-27/8+20×9/4+33×-3/2+18
-27/2+45-99/2+18
(-27+90-99+36)/2
0/2
0
y=-3/2
4(-3/2)^3+20(-3/2)^2+33(-3/2)+18
4×-27/8+20×9/4+33×-3/2+18
-27/2+45-99/2+18
(-27+90-99+36)/2
0/2
0
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truck26:
but the answer was (y +2 ) ( 2y +3)( 2y +3)
plz aap ye answer layiye
do fast
1 minute
ok
I'll do it in a paper
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