factorise :f (x)=x4+x3-7x2-x+6
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Answer:
x4 + x3- 7x2- x + 6/x-1=x3 + 2x2 - 5x - 6. S0 we get. x3 + 2x2 - 5x - 6. Here we have constant term 6 and cofiicient of x3 is 1 ...
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F(2)= 2x2x2x2+ 2x2x2-14-2+6
= 16+8-14-2+6
= 30-14-2
= 30-16
= 14
= 16+8-14-2+6
= 30-14-2
= 30-16
= 14
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