Question

factorise fast pls
p²- pq (1 - q) - q³​

Answer 1

Answer:

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Answer 2

Following are the steps for getting the answer:

Given:

p²- pq (1 - q) - q³​

To find:

factor of p²- pq (1 - q) - q³​

Solution:

we have to find the factor of p²- pq (1 - q) - q³​

so we will solve the bracket first,

p²- pq (1 - q) - q³​

=p²- pq+pq²-q³​

now we will solve it by grouping method

=(p²- pq)+(pq²-q³​)

now we will take out the common p in the (p²- pq) and q² from (pq²-q³​)

we get,

=p(p-q)+q²(p-q)

=(p-q)(p+q²)

thus, the factor of p²- pq (1 - q) - q³​ is (p-q)(p+q²)