factorise
fast plz
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Answer:
\begin{gathered}p {q}^{4} - p(p - q) ^{4} \\ = p( {q}^{4} - (p - q) ^{4} ) \\ = p( {q}^{2} + (p - q) ^{2} )( {q}^{2} - (p - q) ^{2} )\\ = p( {q}^{2} + {p}^{2} + {q}^{2} - 2pq)(q + p - q)(q - p + q) \\ = p(2 {q}^{2} + {p}^{2} - 2pq)(p)(2q - p) \\ = {p}^{2} (2 {q}^{2} + {p}^{2} - 2pq)(2q - p) \end{gathered}
pq
4
−p(p−q)
4
=p(q
4
−(p−q)
4
)
=p(q
2
+(p−q)
2
)(q
2
−(p−q)
2
)
=p(q
2
+p
2
+q
2
−2pq)(q+p−q)(q−p+q)
=p(2q
2
+p
2
−2pq)(p)(2q−p)
=p
2
(2q
2
+p
2
−2pq)(2q−p)
This is your answer.༎ຶ‿༎ຶ
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