Question

factorise following 3x^3-x^2-3x+1​

Answer 1

Step-by-step explanation:

3x^3-x^2-3x+1

3x^3-x^2-3x+1=0

if x=1 then

3(1)^3-(1)^2-3(1)+1=0

3(1)-1-3+1=0

3-1-3+1=0

2-3+1=0

-1+1=0

so (x-1) is factor of above polynomial.

x-1 (3x^3-x^2-3x+1) 3x^2+2x-1

+3x^2-3x^2

(-) (+)

2x^2-3x

+2x^2-2x

( -) (+)

- x+1

-x+1

( +)(-)

( 0)

3x^2+2x-1

product = 3x^2 = 3x ×x

sum = 2x = 3x-x

3x (x+1) -1 (x+1)

(x-1) (3x-1) (x+1)

so although the answer is (x-1) (3x-1) (x+1)

it hope that it helps you thanks