Question

factorise following polynomial
$x3 - 6x + 4$
​

Answer 1

Steps:

$\\\tt {x}^{3} - 6x + 4 \\\tt = {x}^{3} - 4x - 2x + 4\\\tt = x( {x}^{2} - 4) - 2(x - 2) \\\tt = x(x + 2)(x - 2) - 2(x - 2)\\\tt = (x - 2)[x(x + 2) - 2]\\\tt = (x - 2)( {x}^{2} + 2x - 2)$

Formulas used:

$\ \ \tt {x}^{2} - {y}^{2} = (x + y)(x - y)$