factorise fully:
a^2 − b^2 − a + b
Answers
Answered by
0
Answer:
a²-b²-a+b
=(a+b) (a-b) -(a+b)
=(a+b) {(a-b)-1}
=(a+b) (a-b-1)
Step-by-step explanation:
a²-b²-a+b
using identity a²-b²= (a+b) (a-b)
=(a+b) (a-b) -(a+b)
taking (a+b) as common,
=(a+b) {(a-b)-1}
= (a+b) (a-b-1) is the answer
Answered by
104
Answer:
We know the identity
➪ a² – b² = ( a + b ) ( a – b )
Using the above identity, the given expression a² – b² – a + b can be factorised as follows :
➪ a² – b² − a + b = [ ( a + b ) ( a − b ) ]
– 1 ( a − b ) = ( a − b ) ( a + b − 1 )
Hence,
➪ a² – b² – a + b = ( a – b ) ( a + b – 1 )
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