Math, asked by dhanvipatel97, 3 months ago

factorise fully:
a^2 − b^2 − a + b

Answers

Answered by aditi7481
0

Answer:

a²-b²-a+b

=(a+b) (a-b) -(a+b)

=(a+b) {(a-b)-1}

=(a+b) (a-b-1)

Step-by-step explanation:

a²-b²-a+b

using identity a²-b²= (a+b) (a-b)

=(a+b) (a-b) -(a+b)

taking (a+b) as common,

=(a+b) {(a-b)-1}

= (a+b) (a-b-1) is the answer

Answered by xxyogeshxx7
104

Answer:

We know the identity

➪ a² – b² = ( a + b ) ( a – b )

Using the above identity, the given expression a² – b² – a + b can be factorised as follows :

➪ a² – b² − a + b = [ ( a + b ) ( a − b ) ]

– 1 ( a − b ) = ( a − b ) ( a + b − 1 )

Hence,

➪ a² – b² – a + b = ( a – b ) ( a + b – 1 )

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