Question

factorise fully pq-3 rq+pr-3xsquare

Answer 1

Step-by-step explanation:

(p-q)³ + (q-r)³ + (r-p)³

If a³ + b³ + c³ = 0, we can say that a³ + b³ + c³ = 3abc

a³ + b³ + c³ = p³ - q³ + q³ - r³ + r³ - p³ ( positives and negatives are cut )

∴ a³ + b³ + c³ = 0

a³ + b³ + c³= 3abc

= 3 × ( p - q )( q - r )( r - p )

= 3(p-q)(q-r)(r-p)

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