factorise he following:
a. 6x2 x - 1
b. x3 - 23x2 142x - 120
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Answered by
0
HEY!!
6x2 + x - 1
= 6x2 + 3x - 2x - 1
=3x(2x+1) -(2x+1)
=(3x-1)(2x+1)
6x2 + x - 1
= 6x2 + 3x - 2x - 1
=3x(2x+1) -(2x+1)
=(3x-1)(2x+1)
Answered by
2
1.,) 6x²+x-1
6x²+3x-2x-1
3x(2x+1)-(2x+1)
(2x+1)(3x-1)
2.) x³-23x²+142x-120
Let x=1
1-23+142-120
=>0
Hence x-1 is the factor
By dividing, Quotient is x²-22x +120
So by Factorizing it by splitting middle term
x²-22x+120
x²-12x-10x+120
x(x-12)-10(x-12)
(x-12)(x-10)
Hope this helps
6x²+3x-2x-1
3x(2x+1)-(2x+1)
(2x+1)(3x-1)
2.) x³-23x²+142x-120
Let x=1
1-23+142-120
=>0
Hence x-1 is the factor
By dividing, Quotient is x²-22x +120
So by Factorizing it by splitting middle term
x²-22x+120
x²-12x-10x+120
x(x-12)-10(x-12)
(x-12)(x-10)
Hope this helps
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