Factorise
(i) 1-64a^3 -12a+48a^2
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Answer:
1-64a³
=1³-(4a)³
using a³-b³=(a-b) (a²+ab+b²)
= (1-4a) (1²+1*4a+(4a)²)
=(1-4a)(1+4a+16a²)
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