Question

factorise --

(i) 27x^3 + y^3 + z^3 - 9xyz
(ii) 12x^2 - 7x + 1​

Answer 1

Step-by-step explanation:

27x3+y3+ z3-9xyz

= (3x)3+y3+z3+9xyz

=3x3+y3+ z3-3×3x×y×z

l hope you understand please follow me

Answer 2

Answer:

$\huge\red{solutions}$

$\blue{(i) {27x}^{3} + {y}^{3} + {z}^{3} - 9xyz} \\ \blue{ = {(3x)}^{3} + {y}^{3} + {z}^{3} - 3 \times 3x \times y \times z} \\ \blue{ = (3x + y + z)( {(3x)}^{2} + {y}^{2} + {z}^{2} - 3x \times y - y \times z - z \times 3x)} \\ \blue{ = (3x + y + z)( {9x}^{2} + {y}^{2} + {z}^{2} - 3xy - yz - 3zx)}$

$\pink{ (ii){12x}^{2} - 7x + 1} \\ \pink{ = {12x}^{2} - 3x - 4x + 1} \\ \pink{ = 3x(4x - 1) - 1(4x - 1)} \\\pink{ = (4x - 1)(3x - 1)}$