Math, asked by AvaniAgrawal2007, 4 months ago

Factorise:
i. 2x^2 + 10x + 12
ii. y^2– 11y + 18
iii. a^2 – (b^2 + 2bc + c^2)

Answers

Answered by sainiinswag
1

Answer:

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Answer :- 1

2 {x}^{2}  + 10x + 12 \\  \\ 2 {x}^{2}  + 6x + 4x + 12 \\  \\ 2x(x + 3) + 4(x + 3) \\  \\ (x + 3)(2x + 4)

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Answer :- 2

 {y}^{2}  - 11y + 18 \\  \\  {y}^{2}  - 9y - 2y + 18 \\  \\ y(y - 9) - 2(y - 9) \\  \\ (y - 9)(y - 2)

Answer :- 3

 {a}^{2}  - ( {b}^{2}  + 2bc +  {c}^{2} ) \\  \\  =  {a}^{2}  -  {(b + c)}^{2}  \\  \\ use \: identity \:  \:  \:  {a}^{2}  -  {b}^{2}  = (a - b)(a + b) \: we \: have \\  \\ =  [ a - (b + c) ][  a + b + c] \\  \\  = (a - b - c)(a + b + c)

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AvaniAgrawal2007: thanks
sainiinswag: Welcome Dear!!
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