Question

Factorise : (i) 2y+y2- 2y-1

Answer 1

Hi there

Your answer is :-

$2y + y^2 - 2y - 1 = 0$

$y^2 - 1 = 0$

$( y - 1 ) \times ( y + 1 ) = 0$

$y - 1 = 0\:,\:y + 1 = 0$

$y = 1\: ,\: y = - 1$

Thank You

Answer 2

$2y + {y}^{2} - 2y - 1 \\ = {y}^{2} - 1 \\ = {y}^{2} - {1}^{2} \: \: \\ using \: identity \: = > {a }^{2} - {b}^{2} = (a + b)(a - b) \\ = (y + 1)(y - 1)$