Math, asked by someone058, 5 hours ago

Factorise:
i) 4√5x²-17x+3√5
ii) 54x³y - 128 y⁴
iii) (3x-5y)³ (5y-9z³) + (9z-3x)³​

Answers

Answered by himasnhu1167
0

Answer:

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Answered by rajanchayal
0
2. ((54 • (x^3)) • y) - 27y^4

((2•3^3x^3) • y) - 27y^4
Pull out like factors :
54x^3y - 128y^4 = 2y • (27x^3 - 64y^3)

Factoring: 27x^3 - 64y^3
Factorization is :
(3x - 4y) • (9x^2 + 12xy + 16y^2)
Final result :
2y • (3x - 4y) • (9x^2 + 12xy + 16y^2)
3-Answer— (((3x-5y)•3)+((5y-9z)•3))+3•(z-3x)
(((3x-5y)•3)+3•(5y-9z))+3•(z-3x)
(3•(3x-5y)+3•(5y-9z))+3•(z-3x)
Pull out 3
After pulling out, we are left with :
3 • ( 1 * (3x-9z) - (-1) * (z-3x) ))
-24z
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