Factorise :
(i) 64a²b - 144b³ (ii) (2x - y)³ - (2x - y)
(iii) x² - 2xy + y² - z²
(iv) x² - y² - 2yz - z²
Answers
Answered by
2
Answer:
(i)64a^2b-144b^3
=16b(4a^2-9b^2)
=16b{(2a)^2-(3b)^2}
=16b(2a+3b)(2a-3b)
(ii) (2x-y)^3-(2x-y)
=(2x-y){(2x-y)^2-1}
=(2x-y){(2x-y)^2-1^2}
=(2x-y)(2x-y+1)(2x-y-1)
(iii)x^2-2xy+y^2-z^2
=(x-y)^2-z^2
=(x-y+z)(x-y-z)
(iv)x^2-y^2-2yz-z^2
=x^2-(y^2+2yz+z^2)
=x^2-(y+z)^2
=(x+y+z)(x-y-z)
Answered by
0
Answer:
i) 64a²b - 144b³
= 16b ( 4a² - 9b²)
= 16b [ (2a)² - (3b)² ]
= 16b ( 2a - 3b )
use the formula- x² - y² = ( x + y ) ( x - y )
= 16b ( 2a + 3b ) ( 2a - 3b )
ii) (2x - y )³ - (2x - y )
= ( 2x - y ) [ ( 2x - y)² - 1 ]
= ( 2x - y ) ( 2x - y -1 )
use the formula - x² - y² = ( x+ y ) ( x-y )
= ( 2x - y ) ( 2x - y + 1 ) ( 2x - y - 1 )
iii) x² -2xy + y² - z²
= ( x² - 2xy + y² ) - z²
= ( x - y )² - z²
use the formula- ( a + b ) ( a - b ) = a² - b²
= ( x - y + z ) ( x - y - z )
iv) x² - y² - 2yz - z²
= x² - ( y² - 2yz - z² )
= x² - ( y + z)²
use the formula- ( a + b ) ( a - b ) = a² - b²
= ( x + y + z ) ( x - y - z )
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