factorise (i) (a-b)^3+(b-c)^3+(c-a)^3
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Let
(a-b)=a,(b-c)=b and(c-a)=c
we know that
if a+b+c=0 then a^3+b^3+c^3=3abc
a+b+c
putting value of a,b,c
a-b+b-c+c-a=0
so,the value of (a-b)^3+(b-c)^3+(c-a)^3=
3(a-b)(b-c)(c-a)
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