Factorise: i) a³b-a²b + 5ab-5b ii) x² + xy - 2xz-2yz
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Step-by-step explanation:
a
3
b−a
2
b+5ab−5b
By taking a
2
b common in the first two term and 5b as common in the second two term
a
3
b−a
2
b+5ab−5b=a
2
b(a−1)+5ab(a−1)
So we get,
a
3
b−a
2
b+5ab−5b=(a−1)(a
2
b+5b)
By taking b as common. We get,
a
3
b−a
2
b+5ab−5b=b(a−1)(a
2
+5
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