Question

Factorise :
(i) b2 + 2 + 2bc - a​

Answer 1

Step-by-step explanation:

Given (a

2

−2bc−b

2

−c

2

)÷(a−b−c)(a+b+c)

(a−b−c)(a+b+c)=a

2

−ab−ac+ba−b

2

−bc+ca−cb−c

2

=a

2

−b

2

−c

2

−2bc

So,

(a

2

−2bc−b

2

−c

2

)÷(a−b−c)(a+b+c)=

(a−b−c)(a+b+c)

(a

2

−2bc−b

2

−c

2

)

=

(a

2

−2bc−b

2

−c

2

)

(a

2

−2bc−b

2

−c

2

)

=1