Factorise :
(i) p2-9
Answers
Answered by
39
Refer to the attachment for your answer
Attachments:
Answered by
132
✩The method used to break down the factors, or numbers that multiply to form another number is called factorisation.
☞Correct Question:
✩Factorise :
(i) p² - 9
☞Solution:
p² - 9 = p² - 3²
Use identity a² - b²
a² - b² = (a + b) (a - b)
=> p² - 3²
=> p² - (3)² = (p +3) (p - 3)
☞Standard Algebraic Identities:
•(a + b)² = a² + 2ab + b²
•(a - b)² = a² -2ab + b²
•a² - b² = (a + b) (a - b)
•(x + a) (x + b) = x² + (a + b)x + ab
•(a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca
•(a + b)³ = a³ + b³ + 3ab(a + b)
•(a - b)³ = a³ - b³ - 3ab(a - b)
•a³ + b³ + c³ - 3abc = (a + b + c) (a² + b² + c² - ab - bc - ca)
Similar questions