Factorise :-
i wil surely mark the answer as the brainliest.
Attachments:
Answers
Answered by
0
We have 5y2 - 20y = 5y(y - 4)and -8z + 2yz = 2z(-4 + y) = 2z(y - 4)∴ 5y2 - 20y - 8z + 2yz = 5y(y - 4) + 2z(y - 4) = (y - 4)[5y + 2z]
Explanation:
x
2
+
8
x
+
16
=
0
The equation is of the form
a
x
2
+
b
x
+
c
=
0
where:
a
=
1
,
b
=
8
,
c
=
16
The Discriminant is given by:
Δ
=
b
2
−
4
⋅
a
⋅
c
=
(
8
)
2
−
(
4
⋅
1
⋅
16
)
=
64
−
64
=
0
The solutions are found using the formula
x
=
−
b
±
√
Δ
2
⋅
a
x
=
−
8
±
√
0
2
⋅
1
=
−
8
±
0
2
x
=
−
8
+
0
2
=
−
8
2
=
−
4
x
=
−
8
−
0
2
=
−
8
2
=
−
4
Answered by
4
hope this will help you
Attachments:
muktachavhan:
ty
welcome
Similar questions