Question

Factorise

i) x^2 + 2x - 3

ii) x^2 + 5x - 66

iii) 2x^8 + 7x + 3​

Answer 1

Step-by-step explanation:

$i) \: \: {x}^{2} + 2x - 3 \\ \: \: \: \: \: {x}^{2} + 3x - x - 3 \\ \: \: \: \: \: \: \: \: \: x(x + 3) - 1(x+ 3) \\ (x + 3)(x - 1) \\ ii) {x}^{2} + 5x - 66 \\ {x}^{2} + 11x - 6x - 66 \\ x(x + 11) - 6(x + 11) \\( x + 11)(x - 6)$

Answer 2

$\underline{\underline{\huge{\pink{\tt{\textbf Answer :-}}}}}$

$1. \: \: {x}^{2} + 2x - 3 = 0$

${x}^{2} - x + 3x - 3 = 0$

x(x-1)+3(x-1)=0

(x+3)(x-1)=0

$2. \: \: \: {x}^{2} + 5x - 66 = 0$

${x}^{2} + 6x - 11x - 66 = 0$

x(x+6)-11(x+6)=0

(x-11)(x+6)=0

$3. \: \: \: \: 2 {x}^{2} + 7x + 3 = 0$

$2 {x}^{2} + 6x + x + 3 = 0$

2x(x+3)+1(x+3)=0

(2x+1)(x+3)=0