Factorise :-
i) x^8-1
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Answered by
6
hey mate here's ur answer
x^8 - 1
= (x⁴)² - 1²
using a² - b² = (a-b)(a+b)
= (x⁴ - 1)(x⁴ + 1)
= [(x²)² - 1²](x⁴ + 1)
again, using a² - b² = (a-b)(a+b)
= [(x² - 1)(x² + 1)](x⁴ + 1)
= ||ly [(x -1)(x+1)(x²+1)](x⁴ + 1)
sahil64418:
I m just saying u the answer
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