Factorise:
I) x^8 – 256
ii) 9x² – 6x + 1
Answers
Answered by
1
Answer:
sorry I can solve 2nd question not first
Step-by-step explanation:
9x^2-6x+1
9x^2(-3-3)x+1
9x^2-3x-3x+1
3x(3x-1)-1(3x-1).
(3x-1)(3x-1). common
(3x-1)^2
if I am wrong forbidden me......★★
Answered by
3
Step-by-step explanation:
i) x⁸ - 256 = x⁸ - 2⁸
= (x⁶)² - (2⁶)²
= (x⁶-2⁶) (x⁶+ 2⁶)
= {(x³)² - (2³)²} (x⁶+ 2⁶)
= (x³- 2³) (x³+ 2³) (x⁶+ 2⁶)
ii) 9x² -6x +1 = 9x² -3x -3x + 1
= 3x(3x-1) -1(3x-1)
= (3x-1) (3x-1)
Hope that helps!
Pls mark it brainliest!
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