Question

Factorise :i) x²y⁴z⁶–x¹⁶
ii)64a²–25b⁶
iii) (x+2y)²– 1​

Answer 1

Answer:

a (15x - 14y) (x + 14y)

Step-by-step explanation:

I understand that this expression needs to be factorize. Considering it, the solution is given below. Hope it helps

         64ax² - 49a(x-2y)²

Taking a common from both terms

        = a [ 64x² - 49(x-2y)² ]

        = a [ ( 8x )² - { 7( x - 2y )}² ]

Applying a² - b² = (a + b) (a - b), where a = (8x) and b = 7(x-2y)

        = a [ (8x + 7( x - 2y ) ] [ 8x - 7 ( x - 2y ) ]

        = a (8x + 7x - 14y)(8x - 7x + 14y)

       = a (15x - 14y) (x + 14y)

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Answer 2

Answer:

Step-by-step explanation:

x²((y²z³+x⁷)(y²z³-x⁷)).

a²-b² = (a+b)(a-b) = where a = 8a and b = 5b³ ⇒ (8a+5b³)(8a-5b³).

x²+4xy+4y²-1.