Math, asked by manjeetkaur51729, 5 months ago

Factorise :
(i) x3 - 2x2 - x + 2
(iii) x + 13x2 + 32x + 20
(ii) x3 - 3x2 - 9x-5
(iv) 2y3 + y2 – 2y-1

please explain me briefly.... ​

Answers

Answered by pragya3173
1

Answer:

Answer

(i) x

3

−2x

2

−x+2

=x

2

(x−2)−1(x−2)

=(x−2)(x

2

−1)

=(x−2)(x+1)(x−1)

(ii) x

3

−3x

2

−9x−5

=x

3

−5x

2

+2x

2

−10x+x−5

=x

2

(x−5)+2x(x−5)+1(x−5)

=(x−5)(x

2

+2x+1)

=(x−5)(x+1)(x+1)

(iii) x

3

+13x

2

+32+20

Let us put x=1,2,−1,−2 and check if they satisfy the equation.

x=−2 satisfies the equation.

Dividing the equation by (x+2), we get

⇒ x

3

+13x

2

+32+20

=(x+2)(x

2

+11x+10)

=(x+2)(x

2

+x+10x+10)

=(x+2)[x(x+1)+10(x+1)]

=(x+2)(x+1)(x+10)

(iv) 2y

3

+y

2

−2y−1

=2y

3

+2y

2

−y

2

−y−y−1

=2y

2

(y+1)−y(y+1)−1(y+1)

=(y+1){2y

2

−y−1}

=(y+1){2y

2

−2y+y−1}

=(y+1){2y(y−1)+1(y−1)}

=(y−1)(y+1)(2y+1)

Answered by devansh1432
1

Step-by-step explanation:

Here is your answer buddy

Hope it is helpful

I am trying my best for your understanding

Thank you (•‿•)

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