Math, asked by srilaxmi77, 1 year ago

Factorise
if u correctly I will definitely mark u as brainliest

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Answered by siddhu96
3
wait some time I will tell u next answer
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siddhu96: am I correct
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Answered by siddhartharao77
10

(1)

Given : 4(x + y) - 6(x + y)^2

= > 4x + 4y - 6(x^2 + y^2 + 2xy)

= > 4x + 4y - 6x^2 - 6y^2 - 12xy

= > -2(3x^2 + 3y^2 - 2x - 2y + 6xy)

= > -2(3x^2 + 3y^2 - 2x - 2y + 3xy + 3xy)

= > -2(3x^2 + 3xy - 2x + 3xy + 3y^2 - 2y)

= > -2(x(3x + 3y - 2) + y(3x + 3y - 2))

= > -2(x + y)(3x + 3y - 2).

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(2)

Given 32x^2 - 18y^2

= > 2(16x^2 - 9y^2)

= > 2[(4x)^2 - (3y)^2]

We know that a^2 - b^2 = (a + b)(a - b)

= > 2(4x + 3y)(4x - 3y)



Hope this helps!


siddhartharao77: :-)
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