Question

Factorise: ii) 1 – 2y + y^2

iii) x^2+ 12x – 45

iv) a^2+ 3a – 88

Answer 1

Step-by-step explanation:

Factorise: ii) 1 – 2y + y^2

= (1)^2-2(1)(y)+(y)^2

= (1-y)^2

so, 1 – 2y + y^2= (1-Y)^ 2

iii) x^2+ 12x – 45

= x^2+ 15x-3x – 45

=X(X+15)-3(x-15)

=(x-3) (x-15)

so, x^2+ 12x – 45=(x-3)(x-15)

iv) a^2+ 3a – 88

a^2+ 11a – 8a-88

= a(a+11)-8(a+11)

= (a-8) (a+11)

so, a^2+ 3a – 88= (a-8) (a+11)