factorise (ii) 27 -125a' - 135a + 225a²
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Answer:
Answer below......
Step-by-step explanation:
27 - 125a³ - 135a + 225a²
= 3³ + (-5a)³ - 45a(3-5a)
= (3)³ + (-5a)³ + 3×3×(-5a)[3-(-5a)]
= [ 3 + (-5a)]³ = (3 - 5a)³
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