Math, asked by IƚȥSɯҽҽƚCαɳԃყ, 9 months ago

Factorise (ii)
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Answered by Vishal101100

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Answered by Anonymous

Answer:

Factorization. do it in steps.

First take 4x^2 - y^2 - 3xy or [4 (x/y)^2 - 3 (x/y) - 1] * y^2

[ 4 x/y + 1 ] [ x/y - 1 * y^2

( 4x + y) (x - y)

So LET 4 x^2 - y^2 - 3 x y + 2 x - 2 y

= (4x + y + b) (x - y + c)

Multiply and compare coefficients, we get b = 2, c = 0

So answer (4x + y +2 ) (x - y)

Step-by-step explanation:

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