factorise in Quadratic equations(х + 3) (x — 3) = 27
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Let f(x) = x³ + 27
0 = x³ + 27
x³= -27
x = -3
This means that x = -3 is the only zero of the graph of f(x). Since we know (x+3) is one factor of f(x), to find the 2nd factor,
x3+27x+3
We get the second factor to be x2−3x+9.
Therefore, f(x)=(x+3)(x2−3x+9)
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