Question

factorise. it. 16x^4-1​

Answer 1

16x^4-1

= (4x^2)^2 -(1)^2

Using the identity a^2 - b^2 = (a-b)(a+b)

= (4x^2-1)(4x^2+1)

Answer 2

Answer:

[4x^2 - 1] [4x^2 +1]

Step-by-step explanation:

(4x^2)^2 - (1)^2

[4x^2 - 1] [4x^2 + 1]

I think so ...