Factorise it 2x^3+10x^2-48x
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take x common from the equation
you will get
x(2x^2+10x - 48)
= x[2x^2 +(16-6)x - 48]
=x(2x^2+ 16x - 6x - 48)
=x[2x(x+8)-6(x+8)]
=x(2x-6)(x+8)
This the answer
you will get
x(2x^2+10x - 48)
= x[2x^2 +(16-6)x - 48]
=x(2x^2+ 16x - 6x - 48)
=x[2x(x+8)-6(x+8)]
=x(2x-6)(x+8)
This the answer
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