factorise it : 64x³-(2x-t) ³
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Hey dear here is ur answer
(4x) ³-(2x-t) ³
Using formula
=(4x-2x+t) [16x²+(2x-t)²+4x(2x-t)]
=(2x+t) [16x²+4x²+t²-4xt+8x²-4xt]
=(2x+t) [28x²+t²-8xt]
Hope it will help you
(4x) ³-(2x-t) ³
Using formula
=(4x-2x+t) [16x²+(2x-t)²+4x(2x-t)]
=(2x+t) [16x²+4x²+t²-4xt+8x²-4xt]
=(2x+t) [28x²+t²-8xt]
Hope it will help you
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