Math, asked by shagunmishra3244, 7 months ago

factorise it a^3-1/a^3-2a+2/a​

Answers

Answered by Anonymous
7

a³ - 1/a³ - 2a + 2/a

= (a - 1/a){a² + (a × 1/a) + 1/a²} - 2(a - 1/a)

= (a - 1/a)(a² + 1/a² + 1) - 2(a - 1/a)

= (a - 1/a)(a² + 1/a² + 1 - 2)

= (a - 1/a)(a² + 1/a² - 1),

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