Factorise it:
a⁴+3a²+4
plz answer
Answers
Answered by
18
We can write
=> a⁴ + 3a² + 4
as
= a⁴ + 4a² + 4 - a²
Now,
a⁴ = (a²)²
4 = (2)²
and 4a² = 2(a²)(2)
Hence, a⁴ + 4a² + 4 = (a² + 2)²
So, a⁴ + 4a² + 4 - a²
= (a² + 2)² - a²
Now, we know that a² - b² = (a + b)(a - b)
=> (a² + 2)² - a²
= (a² + 2 - a)(a² + 2 + a)
= (a² - a + 2)(a² + a + 2)
=> a⁴ + 3a² + 4
as
= a⁴ + 4a² + 4 - a²
Now,
a⁴ = (a²)²
4 = (2)²
and 4a² = 2(a²)(2)
Hence, a⁴ + 4a² + 4 = (a² + 2)²
So, a⁴ + 4a² + 4 - a²
= (a² + 2)² - a²
Now, we know that a² - b² = (a + b)(a - b)
=> (a² + 2)² - a²
= (a² + 2 - a)(a² + 2 + a)
= (a² - a + 2)(a² + a + 2)
Mankuthemonkey01:
glad to hear :)
Answered by
1
that much big answer u have. written really genius
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