Math, asked by singharchana15468, 2 days ago

Factorise it and Plz Plz Plz send me photos​

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Answers

Answered by anumathsfiles
1

Answer:

Step-by-step explanation:

Whenever we factorise we need to pair the terms and we should take common in such a way that the terms in the brackets should be same.. the same terms in the brackets is to be taken once

i) m²n² + m² + n² + 1

= (m²n² + m²) + (n² + 1)

= m² ( n² + 1 ) + 1 ( n² + 1 )

= ( n² + 1) ( m² + 1)

The factors are  ( n² + 1)and  ( m² + 1)

ii) 5xy² - 5y² - 3a + 3ax

= (5xy² - 5y²) + ( - 3a + 3ax)

= 5y² ( x - 1) + 3a ( -1 + x)

=  5y² ( x - 1) + 3a ( x - 1)

= ( 5y² + 3a) ( x - 1)

The factors are ( 5y² + 3a) and  ( x - 1)

iii) 3xy² - 6y² + 4x - 8

=  (3xy² - 6y²) + (4x - 8)

=  (3xy² - 3 into 2 y²) + (4x - 4 into 2)

= 3y² ( x - 2) + 4 ( x - 2 )

= ( x - 2 ) ( 3y² + 4)

The factors are  ( x - 2 ) and ( 3y² + 4)

iv) 2a² - a²b - bc² + 2c²

= (2a² - a²b)+ ( - bc² + 2c²)

= a² ( 2 - b ) + c² ( -b + 2)

= a² ( 2 - b ) + c² ( 2 -b )

= (a² + c²) ( 2 - b)

The factors are (a² + c²) and ( 2 - b)

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