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Answers
Answer:
Step-by-step explanation:
Whenever we factorise we need to pair the terms and we should take common in such a way that the terms in the brackets should be same.. the same terms in the brackets is to be taken once
i) m²n² + m² + n² + 1
= (m²n² + m²) + (n² + 1)
= m² ( n² + 1 ) + 1 ( n² + 1 )
= ( n² + 1) ( m² + 1)
The factors are ( n² + 1)and ( m² + 1)
ii) 5xy² - 5y² - 3a + 3ax
= (5xy² - 5y²) + ( - 3a + 3ax)
= 5y² ( x - 1) + 3a ( -1 + x)
= 5y² ( x - 1) + 3a ( x - 1)
= ( 5y² + 3a) ( x - 1)
The factors are ( 5y² + 3a) and ( x - 1)
iii) 3xy² - 6y² + 4x - 8
= (3xy² - 6y²) + (4x - 8)
= (3xy² - 3 into 2 y²) + (4x - 4 into 2)
= 3y² ( x - 2) + 4 ( x - 2 )
= ( x - 2 ) ( 3y² + 4)
The factors are ( x - 2 ) and ( 3y² + 4)
iv) 2a² - a²b - bc² + 2c²
= (2a² - a²b)+ ( - bc² + 2c²)
= a² ( 2 - b ) + c² ( -b + 2)
= a² ( 2 - b ) + c² ( 2 -b )
= (a² + c²) ( 2 - b)
The factors are (a² + c²) and ( 2 - b)