factorise it and tell me
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x^3+1/x^3-2=0
Taking LCM
x^6+1-2x^3=0
x^6-2x^3+1=0
Let x^3=p
p^2-2p+1=0
p^2-p-p+1=0
p (p-1)-1 (p-1)=0
(p-1)(p-1)=0
Therfore,p=1
which means x^3=1
.°.x=1
Taking LCM
x^6+1-2x^3=0
x^6-2x^3+1=0
Let x^3=p
p^2-2p+1=0
p^2-p-p+1=0
p (p-1)-1 (p-1)=0
(p-1)(p-1)=0
Therfore,p=1
which means x^3=1
.°.x=1
ashwani3183:
wrong
factorise it I am not understand your w righting
what is it you are not able to understand?
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