Question

factorise it by grouping...
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Answer 1

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Answer 2

Step-by-step explanation:

16.

$a^{2}+\frac{1}{a^{2}}-2-3a+\frac{3}{a}\\\\=(a)^{2}-2*a*\frac{1}{a}+(\frac{1}{a})^{2}-3(a-\frac{1}{a})\\\\=(a-\frac{1}{a})^{2}-3(a-\frac{1}{a})\\\\=(a-\frac{1}{a})((a-\frac{1}{a}-3)$

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17.

x² + y² + x + y + 2xy

=(x)² + 2xy + (y)² + (x + y)

=(x + y)² + (x + y)

=(x + y)(x + y + 1)

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