Question

factorise it please

Answer 1

Hey dude!!

Here's the correct answer

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${a}^{3} - {b}^{3} + 1 + 3ab \\ = {(a)}^{3} + {( - b)}^{3} + {(1)}^{2} - 3 \times a \times ( - b) \times 1 \\ = (a - b + 1) | {(a)}^{2} + { (- b)}^{2} + {1}^{2} - 3a( - b) - 3( - b) \times 1 - 3a \times 1 | \\ = (a - b + 1) ( {a}^{2} + {b}^{2} + 1 + 3ab + 3b - 3a)$
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Hope it helps you dear! :)