Question

factorise it
plz fast
help me​

Answer 1

Answer:

(y-3+y+5) (y-3-y-5)

= -8 (2y+2)

= -16(y+1)

Answer 2

$\\ \\ \\ \\ to \: factorise : \\ \\ \\ \\ ( {y - 3) }^{2} - ( {y + 5)}^{2} \\ \\ \\ \\ = ( {y}^{2} + 9 - 6y) - ( {y}^{2} + 25 + 10y) \\ \\ \\ \\ = {y}^{2} - {y}^{2} - 6y - 10y - 25 + 9 \\ \\ \\ \\ = > - 16y = 16 \\ \\ \\ \\ y = - 1 \: \: \: \:( answer) \\ \\ \\ \\ \\ \\ we \: \: solve \: \: the \: \: following \: \: using \\ these \: \: two \: \: identities : \\ \\ \\ \\ ( {a - b)}^{2} = {a}^{2} + {b}^{2} - 2ab \\ \\ \\ \\ \\ ( {a + b)}^{2} = {a}^{2} + {b}^{2} + 2ab$

Answer is -16(y+1)