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Step-by-step explanation:
Factorising a²-(b-c)²
We know the algebraic identity:
- = (x+y)(x-y)
= [a+(b-c)] [a-(b-c)]
= (a+b-c)(a-b+c)
Therefore,
a²-(b-c)² = (a+b-c)(a-b+c)
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