Question

factorise it

$9x { } ^{2} + 4y {}^{2} + x {}^{2} y { }^{2} + 36$
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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

9x

9x 2

9x 2 +4y

9x 2 +4y 2

9x 2 +4y 2 +16z

9x 2 +4y 2 +16z 2

9x 2 +4y 2 +16z 2 +12xy−16yz−24xz

9x 2 +4y 2 +16z 2 +12xy−16yz−24xz=(3x)

9x 2 +4y 2 +16z 2 +12xy−16yz−24xz=(3x) 2

9x 2 +4y 2 +16z 2 +12xy−16yz−24xz=(3x) 2 +(2y)

9x 2 +4y 2 +16z 2 +12xy−16yz−24xz=(3x) 2 +(2y) 2

9x 2 +4y 2 +16z 2 +12xy−16yz−24xz=(3x) 2 +(2y) 2 +(−4z)

9x 2 +4y 2 +16z 2 +12xy−16yz−24xz=(3x) 2 +(2y) 2 +(−4z) 2

9x 2 +4y 2 +16z 2 +12xy−16yz−24xz=(3x) 2 +(2y) 2 +(−4z) 2 +2(3x)(2y)+2(2y)(−4z)+2(−4z)(3x)

9x 2 +4y 2 +16z 2 +12xy−16yz−24xz=(3x) 2 +(2y) 2 +(−4z) 2 +2(3x)(2y)+2(2y)(−4z)+2(−4z)(3x)=(3x+2y−4z)

9x 2 +4y 2 +16z 2 +12xy−16yz−24xz=(3x) 2 +(2y) 2 +(−4z) 2 +2(3x)(2y)+2(2y)(−4z)+2(−4z)(3x)=(3x+2y−4z) 2

9x 2 +4y 2 +16z 2 +12xy−16yz−24xz=(3x) 2 +(2y) 2 +(−4z) 2 +2(3x)(2y)+2(2y)(−4z)+2(−4z)(3x)=(3x+2y−4z) 2

9x 2 +4y 2 +16z 2 +12xy−16yz−24xz=(3x) 2 +(2y) 2 +(−4z) 2 +2(3x)(2y)+2(2y)(−4z)+2(−4z)(3x)=(3x+2y−4z) 2 =(3x+2y−4z)(3x+2y−4z)

9x 2 +4y 2 +16z 2 +12xy−16yz−24xz=(3x) 2 +(2y) 2 +(−4z) 2 +2(3x)(2y)+2(2y)(−4z)+2(−4z)(3x)=(3x+2y−4z) 2 =(3x+2y−4z)(3x+2y−4z)Hence facorise.

9x 2 +4y 2 +16z 2 +12xy−16yz−24xz=(3x) 2 +(2y) 2 +(−4z) 2 +2(3x)(2y)+2(2y)(−4z)+2(−4z)(3x)=(3x+2y−4z) 2 =(3x+2y−4z)(3x+2y−4z)Hence facorise.Formula:

9x 2 +4y 2 +16z 2 +12xy−16yz−24xz=(3x) 2 +(2y) 2 +(−4z) 2 +2(3x)(2y)+2(2y)(−4z)+2(−4z)(3x)=(3x+2y−4z) 2 =(3x+2y−4z)(3x+2y−4z)Hence facorise.Formula:(a+b+c)

9x 2 +4y 2 +16z 2 +12xy−16yz−24xz=(3x) 2 +(2y) 2 +(−4z) 2 +2(3x)(2y)+2(2y)(−4z)+2(−4z)(3x)=(3x+2y−4z) 2 =(3x+2y−4z)(3x+2y−4z)Hence facorise.Formula:(a+b+c) 2

9x 2 +4y 2 +16z 2 +12xy−16yz−24xz=(3x) 2 +(2y) 2 +(−4z) 2 +2(3x)(2y)+2(2y)(−4z)+2(−4z)(3x)=(3x+2y−4z) 2 =(3x+2y−4z)(3x+2y−4z)Hence facorise.Formula:(a+b+c) 2 =a

9x 2 +4y 2 +16z 2 +12xy−16yz−24xz=(3x) 2 +(2y) 2 +(−4z) 2 +2(3x)(2y)+2(2y)(−4z)+2(−4z)(3x)=(3x+2y−4z) 2 =(3x+2y−4z)(3x+2y−4z)Hence facorise.Formula:(a+b+c) 2 =a 2

9x 2 +4y 2 +16z 2 +12xy−16yz−24xz=(3x) 2 +(2y) 2 +(−4z) 2 +2(3x)(2y)+2(2y)(−4z)+2(−4z)(3x)=(3x+2y−4z) 2 =(3x+2y−4z)(3x+2y−4z)Hence facorise.Formula:(a+b+c) 2 =a 2 +b

9x 2 +4y 2 +16z 2 +12xy−16yz−24xz=(3x) 2 +(2y) 2 +(−4z) 2 +2(3x)(2y)+2(2y)(−4z)+2(−4z)(3x)=(3x+2y−4z) 2 =(3x+2y−4z)(3x+2y−4z)Hence facorise.Formula:(a+b+c) 2 =a 2 +b 2

9x 2 +4y 2 +16z 2 +12xy−16yz−24xz=(3x) 2 +(2y) 2 +(−4z) 2 +2(3x)(2y)+2(2y)(−4z)+2(−4z)(3x)=(3x+2y−4z) 2 =(3x+2y−4z)(3x+2y−4z)Hence facorise.Formula:(a+b+c) 2 =a 2 +b 2 +c

9x 2 +4y 2 +16z 2 +12xy−16yz−24xz=(3x) 2 +(2y) 2 +(−4z) 2 +2(3x)(2y)+2(2y)(−4z)+2(−4z)(3x)=(3x+2y−4z) 2 =(3x+2y−4z)(3x+2y−4z)Hence facorise.Formula:(a+b+c) 2 =a 2 +b 2 +c 2

9x 2 +4y 2 +16z 2 +12xy−16yz−24xz=(3x) 2 +(2y) 2 +(−4z) 2 +2(3x)(2y)+2(2y)(−4z)+2(−4z)(3x)=(3x+2y−4z) 2 =(3x+2y−4z)(3x+2y−4z)Hence facorise.Formula:(a+b+c) 2 =a 2 +b 2 +c 2 +2ab+2bc+2ca

Step-by-step explanation:

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