Question

Factorise it
Urgent answer please

Answer 1

Solution :

Given :

(2a-3)² -2(2a-3)×(a-1)+(a+1)²

Use the formula (x-y)² = x² - 2xy + y² and expand the expression (2a-3)²

Distribute -2 through the parentheses in -2(2a-3)

Use the formula (x+y)² = x² + 2xy +y² and expand the expression (a+1)²

After doing all these things , we get this equation

4a² - 12a + 9 + (-4a + 6 ) × (a - 1)+ a² + 2a +1

Now , multiply the parentheses

The equation is 4a² - 12a + 9 - 4a² + 4a + 6a - 6 + a² + 2a + 1

Eliminate the opposites i.e. cancel the same numbers with positive and negative signs.

We get 0 + 4 + a²

Remove zero from the equation because even if we add or subtract the equation , there won't be any change

The final answer is 4 + a ²

Note :

Parentheses means the numbers which are in brackets