Math, asked by ronymandal6929, 11 months ago


Factorise it.urgently required.​

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Answers

Answered by sanskriti83
1

Answer:

here is the right answer

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Answered by dhruv829
0

Answer:

by quadratic formula

b^2-4ac

=(-10)^2-4×3×(-8)

=100+32=132

since b^2-4ac>0

it has two distinct roots

x=(-b plusminus √b^2-4ac)/2a

=[-(-10)plusminus√132]/2×3

=[10plusminus2√33]/6

=2[5plusminus√33]/6

=[5plusminus√33]/3

so X=(5+√33)/3and (5-√33)/3

Hope it will be helpful.

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