Question

Factorise it.urgently required.​

Answer 1

Answer:

here is the right answer

Answer 2

Answer:

by quadratic formula

b^2-4ac

=(-10)^2-4×3×(-8)

=100+32=132

since b^2-4ac>0

it has two distinct roots

x=(-b plusminus √b^2-4ac)/2a

=[-(-10)plusminus√132]/2×3

=[10plusminus2√33]/6

=2[5plusminus√33]/6

=[5plusminus√33]/3

so X=(5+√33)/3and (5-√33)/3

Hope it will be helpful.