factorise it... using algebraic identities...
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Let (2x + 1) be "a"
∴ Equation is a² - 10a + 25 = 0
= (a -5)² = 0
∴ But a = (2x + 1)
∴ (2x + 1 - 5)² = 0
∴ (2x - 4)² = 0
∴ (x - 2)² = 0
PLZ MARK AS BRAINLEST
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