Question

Factorise it
((X+2)^2)-((x+4)^2)

Answer 1

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$\huge\boxed{Answer:}$

${(x + 2)}^{2} - {(x + 4)}^{2} = 0\\ {x}^{2} + 4 + 4x - ( {x}^{2} + 16 + 8x) = 0$

${x}^{2} + 4x + 4 - {x}^{2} - 16 - 8x = 0$

$- 4x - 12 = 0$

$- 4(x + 3) = 0 \\ x + 3 =0 \\ x = - 3$

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Answer 2

$\huge{\underline{\underline{\mathfrak{Answer}}}}$

$= > {(x + 2)}^{2} - {(x + 4)}^{2} = 0$

$= > {x}^{2} + 4x + 4 - ( {x}^{2} + 16x + 8x) = 0$

$= > {x}^{2} + 4x + 4 - {x}^{2} - 16 - 8x = 0$

$= > - 4 x - 12 = 0$

$= > - 4(x + 3) = 0$

$= > x + 3 = 0$

$= > x = - 3$

$answer = x - 3$

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$\huge{\underline{\underline{\mathfrak{Thank you}}}}$