Factorise it :
y^3 + 2y^2 - 5y - 6
Answers
Answer:
Question:- How do you factorize y^3-2y^2-5y+6?
Ans:- one of the method of solving the given equation is as follows.
Step 1: Find factors of the constant (6) that is without any variable in the given equation .
Factors of 6=±1,±2,±3,±6
Now put these values one by one to check if they are roots of the given equation or not. Keep in mind as its cubic polynomial so it will have 3 roots.
Put x=1
y^3-2y^2-5y+6=0
1-2-5+6=0
-1-5+6=0
0=0
This means 1 is the root of given equation.-1 is not the roots as it does not satisfy the given equation.I am just solving for roots here.
Put x=-2
y^3-2y^2-5y+6=0
-2^3-2(-2)^2-5*-2+6=0
-8-8+10+6=0
-16+16=0
0=0
So x=-2 is also the root of given equation now we have top find the last root as
For x=3
y^3-2y^2-5y+6=0
3^3-2(3)^2-5*3+6=0
27-18-15+6=0
9-15+6=0
9-9=0
0=0
Hence we have found the three roots of given equation as
Solution set={1,-2,3}
hope this would help you and Mark it as brainliest answer. and you can be my friend.
Step-by-step explanation:
3y³+2y²-5y-6
Taking common
y(3y²+2y-5)-6
y(3y²-3y+5y-5)-6
y(3y(y-1)+5(y-1))-6
y(y-1)(3y+5)-6
hope this helps you
please mark my answer as brainliest ....
staysafedear