Math, asked by kalmednyaneshwar78, 9 months ago

factorise
k^-2k-120​

Answers

Answered by bhumijasingh725
1

Answer:

(k+10)(k-12)

Step-by-step explanation:

k^2-2k-120

=k^2-(12-10)k-120

=k^2-12k+10k-120

=k(k-12)+10(k-12)

=(k+10)(k-12)

Answered by ramuannaramu265
2

Answer:

k=-10,12

Step-by-step explanation:

k²-2k-120

k²+10k-12k-120

k(k+10)-12(k+10)

k-12=0,k+10=0

k=12,k=-10

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