Factorise karo fast.
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x^6 - y ^6
=( x^2)^3 - (y^2)^3
=( x^2 - y^2) ( x^4 + x^2y2 + y ^4 )
=( x - y ) (x + y ) ( x^4 + x^2 y^2 + y^4 )
◆hope it helps ◆
=( x^2)^3 - (y^2)^3
=( x^2 - y^2) ( x^4 + x^2y2 + y ^4 )
=( x - y ) (x + y ) ( x^4 + x^2 y^2 + y^4 )
◆hope it helps ◆
TheLostMonk:
thank-you
Answered by
1
(x^3)^2-(y^3)^2
=(x^3 + y^3)(x^3 -y^3)
={(x-y)(x^2+xy+y^2)}{(x+y)(x^2-xy+y^2)}
is your answer
=(x^3 + y^3)(x^3 -y^3)
={(x-y)(x^2+xy+y^2)}{(x+y)(x^2-xy+y^2)}
is your answer
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