Question

factorise: -
(l+m) ² - 4lm

Answer 1

Hola


Here is your answer


(l+m)^2 - 4lm

l^2 + 2lm + m^2 - 4lm


By identity 1 - (a + b)^2 = a^2 + 2ab +b^2


l^2 -2lm+ m^2


as 2lm - 4lm= -2lm


thus,


Answer

l^2 - 2lm + m^2


Hope it helps

Answer 2

(l+m) *2-4lm . By using identity (a+b) whole square =(a) square +2(a).(b)+(b)square
=(l) square +2(l).(m)+(m) square - 4lm
=l square +2lm+m square -4lm
=l square +2lm-4lm+m square
=l square - 2lm+m square

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